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The given turing machine accepts
- a)Set of all even palindromes over {0,1).
- b)Strings over {0, 1} containing even number of 1’s.
- c)Strings over {0, 1} containing even number of 1 ’s and odd noumber of 0’s.
- d)String over {0,1} starting with zero.
Correct answer is option 'B'. Can you explain this answer?
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The given turing machine acceptsa)Set of all even palindromes over {0,...
It can be observed from the image that this machine will accept only those strings which contains even number of 1’s. And strings with odd number of 1 ’s are rejected.
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The given turing machine acceptsa)Set of all even palindromes over {0,...
The given Turing machine accepts strings over {0, 1} containing an even number of 1.
Here is a high-level description of how the Turing machine would work:
1. Start in the initial state.
2. Read the input symbol.
3. If the input symbol is a 0, move to the next symbol and stay in the same state.
4. If the input symbol is a 1, move to the next symbol and transition to a new state that checks for the next 1.
5. If the input symbol is blank (end of input), move to the next symbol and transition to a new state that checks if the number of 1's seen so far is even or odd.
6. If the number of 1's seen so far is even, accept the input.
7. If the number of 1's seen so far is odd, reject the input.
The Turing machine moves through the input symbols, keeping track of the number of 1's seen so far. If it encounters an odd number of 1's, it rejects the input. If it reaches the end of the input with an even number of 1's, it accepts the input.
Here is a high-level description of how the Turing machine would work:
1. Start in the initial state.
2. Read the input symbol.
3. If the input symbol is a 0, move to the next symbol and stay in the same state.
4. If the input symbol is a 1, move to the next symbol and transition to a new state that checks for the next 1.
5. If the input symbol is blank (end of input), move to the next symbol and transition to a new state that checks if the number of 1's seen so far is even or odd.
6. If the number of 1's seen so far is even, accept the input.
7. If the number of 1's seen so far is odd, reject the input.
The Turing machine moves through the input symbols, keeping track of the number of 1's seen so far. If it encounters an odd number of 1's, it rejects the input. If it reaches the end of the input with an even number of 1's, it accepts the input.
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The given turing machine acceptsa)Set of all even palindromes over {0,1).b)Strings over {0, 1} containing even number of 1’s.c)Strings over {0, 1} containing even number of 1 ’s and odd noumber of 0’s.d)String over {0,1} starting with zero.Correct answer is option 'B'. Can you explain this answer?
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